A certain type of storage battery lasts, on average, 3.0 years with a standard deviation of 0.5 year. Assuming that the battery lives are normally distributed, find the probability that a given battery will last less than 2.3 years.
Let X be the battery lifetime, "X\\sim N\\left( 3,0.5^2 \\right)"
Then
"P\\left( X\\leqslant 2.3 \\right) =P\\left( \\frac{X-3}{0.5}\\leqslant \\frac{2.3-3}{0.5} \\right) =P\\left( Z\\leqslant -1.4 \\right) =\\\\=\\varPhi \\left( -1.4 \\right) =0.08076"
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