a) there are no restrictions?
b) there must be at least one boy chosen?
c) there must be only one girl chosen?
Solution
a. No restriction
n=11, r=3
nPr= n!/(n-r)!
=11!/(11-3)!
=990 ways
b. At least on boy chosen
11P3 - 5P3
=11!/(11-3)! – 5!/(5-3)!
= 990 – 60
= 930 ways
c. Only one girl chosen
5P1 * 6P2 * 3
=5!/(5-1)! * 6!/(6-2)! * 3
=450 ways
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