What is the standard deviation of sampling distribution if standard deviation of population is 35 and sample size is 9?
Let "\\sigma_x" be a standard deviation of sampling distribution, "\\sigma" - population standard deviation, n - sample size, then
"{\\sigma}_x={\\frac {{\\sigma}} {\\sqrt n}}={\\frac {35} {\\sqrt 9}}={\\frac {35} 3}\\approx11.67"
Comments
Leave a comment