
b) μ=28,σ=4,n=2000,Z=(x−μ)/σ
P(x<20)=P(Z<(20−28)/4)=P(Z<−2)
P(Z<−2)=0.0228
Number of applicants = 2000×0.0228=45.6
Thus approximately 46 applicants
c) P(X>30)=P(Z>(30−28)/4)=P(Z>0.5)
=1−P(Z<0.5)=1−0.6915=0.3085
Number of applicants =2000×0.3085=617
d) P(24<x<32)=P((24−28)/4<Z<(32−28)/4)=P(−1<Z<1)
=P(Z<1)−P(Z<−1)
=0.8413−0.1587
=0.6826
Number of applicants =2000×0.6826=1365.2
Thus approximately 1365 applicants.