Question #307788

A random variable X has a normal distribution with mean 50 and variance of 10. Find the range of scores that lie:


A.Within one standard deviation from the mean.


B.Within two standard deviation from the mean.



1
Expert's answer
2022-03-09T12:00:31-0500


Mean: μ=50;\mu=50;

variance: σ2=10;\sigma^2=10;

standard deviation: σ=103.16.\sigma=\sqrt{10} \approx3.16.


A. The range of scores that lie within one standard deviation from the mean:

(μσ,μ+σ)=(503.16,50+3.16)=(\mu-\sigma, \mu+\sigma) =(50-3.16, 50+3.16)=

=(46.84,53.16).=(46.84, 53.16).


B. The range of scores that lie within two standard deviations from the mean:

(μ2σ,μ+2σ)=(5023.16,50+23.16)=(\mu-2\sigma, \mu+2\sigma) =(50-2\cdot3.16, 50+2\cdot3.16)=

=(43.68,56.32).=(43.68, 56.32).







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