Answer to Question #307753 in Statistics and Probability for French

Question

The probabilities of a machine manufacturing 0, 1, 2, 3, 4, or 5 defective parts in one day are 0.50, 0.19, 0.22, 0.025, 0.19,0.06 and 0.005, respectively. Find the mean of the probability distribution

Answer 1

Given that

x P(x)

0 (0.5)

1 (0.19)

2 (0.22)

3 (0.025)

4 (0.06)

5 (0.005)

Then, the mean is computed using the formula:

$\mu$_x=Σx.P(x)

= 0(0.5) + 1(0.19) + 2(0.22) + 3(0.025) + 4(0.06) +5(0.005)

= 0.97

Answer: 0.97