Question #307752

The probabilities of a machine manufacturing 0,1,2,3,4,5 defective parts ln one day are 0.50, 0.22,0.19, 0.025, 0.06 and 0.005 respectively. Find the mean of the probability distribution

1
Expert's answer
2022-03-09T09:55:50-0500

μ=00.50+10.22+20.19+30.025+μ=0\cdot0.50+1\cdot0.22+2\cdot0.19+3\cdot0.025+

+40.06+50.005=0.94.+4\cdot0.06+5\cdot0.005=0.94.




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