Question

I feel my adults with smart phones are randomly selected 64% use them in meetings or classes if five adults smart phone users are randomly selected find the probability that exactly 3 of them use their smart phones and meetings our classes

Answer 1

Solution;

Given;

$P=0.64$

$n=5$

$x=3$

Then;

$q=1-p=1-0.64=0.36$

Using binomial distribution;

$P(X=x)=\frac{n!}{(n-x)!x!}p^xq^{n-x}$

By direct substitution;

$P(X=3)=\frac{5!}{2!×3!}×0.64^3×0.36^2$

$P(X=3)=0.3397$