A manufacturer of light bulbs produces bulbs that last a mean of 950 hours with a standard deviation of 120hours .what is the probability that the mean lifetime of a random sample of 10 of these bulbs is less than 900 hours
P(Xˉ<900)=P(Z<900−95012010)=P(Z<−1.32)=0.0934.P(\bar X<900)=P(Z<\frac{900-950}{\frac{120}{\sqrt{10}}})=P(Z<-1.32)=0.0934.P(Xˉ<900)=P(Z<10120900−950)=P(Z<−1.32)=0.0934.
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