The scores of all pro golfers for a course are normally distributed with the mean of 70 and a standard deviation of 3. Suppose 36 pro golfers played the course today. Find the probability that the mean score of the 36 pro golfers exceeded 71.
"P(\\bar X>71)=P(Z>\\frac{71-70}{\\frac{3}{\\sqrt{36}}})=P(Z>2)=1-P(Z<2)=0.0228."
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