If N1 = 10 and N2 =9 are the sizes where 9 and 10 are the mean of the data respectively then find the 10th number.
μ=SumofallnumbersNumbersizes\mu=\dfrac{Sum of all numbers}{Number sizes}μ=NumbersizesSumofallnumbers
Sum =μ×N= \mu\times N=μ×N
Sum1 =9×10=90=9\times10 =90=9×10=90
Sum2=10×9=90=10\times9=90=10×9=90
The 10th number =90−90=90-90=90−90
=0=0=0
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