Answer to Question #307406 in Statistics and Probability for Lily

Question

Find the mean variance and standard deviation of the following probability

Z. 2. 6. 8. 10. 12

P(z). 0.35. 0.24. 0.20. 0.15. 0.06

Answer 1

$\mu=2*0.35+6*0.24+8*0.20+10*0.15+12*0.06=5.96.$

$\sigma^2=2^2*0.35+6^2*0.24+8^2*0.20+10^2*0.15+12^2*0.06-5.96^2=10.9584.$

$\sigma=\sqrt{10.9584}=3.3103.$