Four coins are tossed. Let Z be the random variable representing the number of heads that occur. Find the values of the random variable Z. Construct a probability distribution and draw the corresponding histogram
Z ~ BIN(4, 0.5), so Z = {0, 1, 2, 3, 4}
P(Z=0)=(40)∗(12)4=116P(Z=0)={4 \choose 0}*({\frac 1 2})^4={\frac 1 {16}}P(Z=0)=(04)∗(21)4=161
P(Z=1)=(41)∗(12)4=416=14P(Z=1)={4 \choose 1}*({\frac 1 2})^4={\frac 4 {16}}={\frac 1 4}P(Z=1)=(14)∗(21)4=164=41
P(Z=2)=(42)∗(12)4=616=38P(Z=2)={4 \choose 2}*({\frac 1 2})^4={\frac 6 {16}}={\frac 3 8}P(Z=2)=(24)∗(21)4=166=83
P(Z=3)=(43)∗(12)4=416=14P(Z=3)={4 \choose 3}*({\frac 1 2})^4={\frac 4 {16}}={\frac 1 4}P(Z=3)=(34)∗(21)4=164=41
P(Z=4)=(44)∗(12)4=116P(Z=4)={4 \choose 4}*({\frac 1 2})^4={\frac 1 {16}}P(Z=4)=(44)∗(21)4=161
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