Question #30687

Calculate the variance for the following population. 1,2, 4,6,6,6,8,11,13

Calculate the variance of the following sample. 1,4,8, 9, 9, 10, 14, 18

Expert's answer

Calculate the variance for the following population. 1,2, 4,6,6,6,8,11,13

Calculate the variance of the following sample. 1,4,8, 9, 9, 10, 14, 18

In probability theory and statistics, the variance is a measure of how far a set of numbers is spread out. It is one of several descriptors of a probability distribution, describing how far the numbers lie from the mean (expected value).

The variance of a set of n equally likely values can be written as


Var(x)=1ni=1n(xiμ)2Var(x) = \frac{1}{n} \sum_{i=1}^{n} (x_i - \mu)^2


where μ\mu is the expected value, μ=1ni=1nxi\mu = \frac{1}{n} \sum_{i=1}^{n} x_i

1. Population: 1,2, 4,6,6,6,8,11,13

expected value μ=19(1+2+4+6+6+6+8+11+13)=193=6.33\mu = \frac{1}{9} (1 + 2 + 4 + 6 + 6 + 6 + 8 + 11 + 13) = \frac{19}{3} = 6.33

variance: Var(x)=19i=19(xi6.33)2=1229=13.56Var(x) = \frac{1}{9} \sum_{i=1}^{9} (x_i - 6.33)^2 = \frac{122}{9} = 13.56

Answer: 13.56

2. Sample: 1,4,8, 9, 9, 10, 14, 18

expected value μ=18(1+4+8+9+9+10+14+18)=738=9.125\mu = \frac{1}{8} (1 + 4 + 8 + 9 + 9 + 10 + 14 + 18) = \frac{73}{8} = 9.125

variance: Var(x)=18i=18(xi9.125)2=24.61Var(x) = \frac{1}{8} \sum_{i=1}^{8} (x_i - 9.125)^2 = 24.61

Answer: 24.61

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