- Let P(B) be the probability that the chosen student is a boy
- Let P(GB) be the probability that the chosen student has blood group B
- Let P(B&GB) be the probability that the chosen student is a boy and has blood group B
- Let P(B/GB) be the probability that the chosen student is a boy or has blood group
P(B)=248=31
P(GB)=21
P(BandGB)=248×21=61
P(BorGB)=P(B)+P(GB)−P(BandGB)
=31+21−61=32
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