Answer to Question #306715 in Statistics and Probability for hanijane

Question

find the mean of the probability distribution of the random variable X if P(X)=⅒, for X= 1,2,2....,10

Answer 1

$\mu=1\cdot0.1+2\cdot0.1+3\cdot0.1+4\cdot0.1+5\cdot0.1+$

$+6\cdot0.1+7\cdot0.1+8\cdot0.1+9\cdot0.1+10\cdot0.1=$

$=(1+2+3+4+5+6+7+8+9+10)\cdot0.1=$

$=55\cdot0.1=5.5$