The average expenditure per student (based on average daily attendance) for a certain school year was $10,337 with a population standard deviation of $1560. A survey for the next school year of 150 randomly selected students resulted in a sample mean of $10, 798. Find the Z statistics? Should the null hypothesis be rejected at alpha = .05 level of significance?
Solution
µ=10337
standard deviation=1560
sample mean(X) = 10798
n=150
H0:µ=10337
H1:µ≠10337
Z0=x-µ/(s.d/sqrt(n))
Z0=10798-10337/(1560/sqrt(150))
=3.6193
From normal tables get 0.0003
α=0.05
from standard normal table two tailed Zα/2=1.96
if Z0>Zα we reject H0
0.0003<1.96
Yes the null hypothesis is rejected at α=0.05
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