Question #306020

Suzan is taking part in five competitions. The probability of her winning any competition is 0.4. (a) Find the probability of her winning at most two competitions. (3 marks) (b) Find the average and standard deviation of this distribution (3 mark


1
Expert's answer
2022-03-07T05:08:03-0500

Let X be a random variable representing the number of winning competitions, then X ~ BIN(5, 0.4)

a) P(X2)=P(X=0)+P(X=1)+P(X=2)=(50)0.400.65+(51)0.410.64+(52)0.420.63=0.68256P(X≤2)=P(X=0)+P(X=1)+P(X=2)={5 \choose 0}*0.4^0*0.6^5+{5 \choose 1}*0.4^1*0.6^4+{5 \choose 2}*0.4^2*0.6^3=0.68256

б) E(X)=50.4=2E(X)=5*0.4=2

σ(X)=50.40.6=1.21.095\sigma(X)=\sqrt{5*0.4*0.6}=\sqrt{1.2}\approx1.095


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS