Question #305559

Direction: Solve the problem below and construct probability distribution and make a histogram.




Suppose three cellphones are tested at random. We want to find out the number of defective cellphones that occur. Thus, to each outcome in the sample space we shall assign a value.

1
Expert's answer
2022-03-04T12:21:30-0500

Let DD represent the defective and NN represent non-defective cellphone. Let XX be the random variable representing the number of defective cell phones.

Sample space:


S={NNN,NND,NDN,DNN,S=\{NNN,NND, NDN,DNN,


NDD,DND,DDN,DDD}NDD, DND, DDN,DDD\}

The possible values of the random variable XX are 0,1,2,3.0, 1, 2, 3.

Possible OutcomesXNNN0NND1NDN1DNN1NDD2DND2DDN2DDD3\def\arraystretch{1.5} \begin{array}{c:c} Possible \ Outcomes & X \\ \hline NNN & 0\\ \hdashline NND & 1 \\ \hdashline NDN & 1 \\ \hdashline DNN & 1 \\ \hdashline NDD & 2 \\ \hdashline DND & 2 \\ \hdashline DDN & 2 \\ \hdashline DDD & 3 \\ \hdashline \end{array}


We will assume that the probability of getting heads and tails is the same:


p=q=1/2p = q =1/2



Construct the probability distribution of the random variable


x0123p(x)1/83/83/81/8\def\arraystretch{1.5} \begin{array}{c:c} x & 0 & 1 & 2 & 3 \\ \hline p(x) & 1/8 & 3/8 & 3/8 & 1/8 \end{array}

or


x0123p(x)0.1250.3750.3750.125\def\arraystretch{1.5} \begin{array}{c:c} x & 0 & 1 & 2 & 3 \\ \hline p(x) & 0.125 & 0.375 & 0.375 & 0.125 \end{array}







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