Let X= the number of females employees selected. The possible values of the random variable X are 0,1,2,3,4,5.
There are (56+6)=792
P(X=0)=(512)(06)(5−06)
=7921(6)=1321
P(X=1)=(512)(16)(5−16)
=7926(15)=13215
P(X=2)=(512)(26)(5−26)
=79215(20)=13250
P(X=3)=(512)(36)(5−36)
=79220(15)=13250
P(X=4)=(512)(46)(5−46)
=79215(6)=13215
P(X=5)=(512)(56)(5−56)
=7926(1)=1321
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