Let's denote R - red ball, B - blue ball.
Sample space S is all possible outcomes.
S={BB,BR,RB,RR}The possible values of the random variable R are 0,1,2.
We will assume that the probability of getting heads and tails is the same:
p=q=1/2Possible OutcomesBBBRRBRRR0112
Construct the probability distribution of the random variable
P(BB)=95(84)=185
P(BR)=95(84)=185
P(RB)=94(85)=185
P(RR)=94(83)=183
rp(r)05/1815/923/18
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