Question #305307

Two balls are drawn in succession without replacement from an urn containing 4 red balls and 5 blue balls. Let R be the random variable representing the number of red balls. Find the values of the random variable R

1
Expert's answer
2022-03-07T08:25:06-0500

Let's denote R - red ball, B - blue ball.

Sample space S is all possible outcomes.


S={BB,BR,RB,RR}S=\{BB, BR, RB, RR\}

The possible values of the random variable RR are 0,1,2.0, 1, 2.

We will assume that the probability of getting heads and tails is the same:


p=q=1/2p = q =1/2Possible OutcomesRBB0BR1RB1RR2\def\arraystretch{1.5} \begin{array}{c:c} Possible \ Outcomes & R \\ \hline BB & 0 \\ \hdashline BR & 1 \\ \hdashline RB & 1 \\ \hdashline RR & 2 \\ \end{array}


Construct the probability distribution of the random variable


P(BB)=59(48)=518P(BB)=\dfrac{5}{9}(\dfrac{4}{8})=\dfrac{5}{18}

P(BR)=59(48)=518P(BR)=\dfrac{5}{9}(\dfrac{4}{8})=\dfrac{5}{18}

P(RB)=49(58)=518P(RB)=\dfrac{4}{9}(\dfrac{5}{8})=\dfrac{5}{18}

P(RR)=49(38)=318P(RR)=\dfrac{4}{9}(\dfrac{3}{8})=\dfrac{3}{18}

r012p(r)5/185/93/18\def\arraystretch{1.5} \begin{array}{c:c} r & 0 & 1 & 2 \\ \hline p(r) & 5/18 & 5/9 & 3/18 \end{array}


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