let the random variable x represent the number of boys in the family construct the probability distribution for the family of two children
P(X=0)=(12)2=14.P(X=0)=(\frac{1}{2})^2=\frac{1}{4}.P(X=0)=(21)2=41.
P(X=1)=(12)2∗2=12.P(X=1)=(\frac{1}{2})^2*2=\frac{1}{2}.P(X=1)=(21)2∗2=21.
P(X=2)=(12)2=14.P(X=2)=(\frac{1}{2})^2=\frac{1}{4}.P(X=2)=(21)2=41.
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