Determine the mean, variance and standard deviation of the probability mass fucntion:
X: 0,1,2,3,4
P(x): 0.1, 0.2, 0.3, 0.3, 0.1
thanks!!!
M(X)=0∗0.1+1∗0.2+2∗0.3+3∗0.3+4∗0.1=2.1M(X)=0*0.1+1*0.2+2*0.3+3*0.3+4*0.1=2.1M(X)=0∗0.1+1∗0.2+2∗0.3+3∗0.3+4∗0.1=2.1
V(X)=M(X2)−M2(X)=02∗0.1+12∗0.2+22∗0.3+32∗0.3+42∗0.1−2.12=5.7−4.41=1.29V(X)=M(X^2)-M^2(X)=0^2*0.1+1^2*0.2+2^2*0.3+3^2*0.3+4^2*0.1-2.1^2=5.7-4.41=1.29V(X)=M(X2)−M2(X)=02∗0.1+12∗0.2+22∗0.3+32∗0.3+42∗0.1−2.12=5.7−4.41=1.29
σ(X)=V(X)=1.29≈1.136\sigma(X)=\sqrt{V(X)}=\sqrt{1.29}\approx1.136σ(X)=V(X)=1.29≈1.136
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