the weights of 1000 children have average of 45 kilograms and a standard deviation of 5 kilograms, how many children weight 35 kg to 55 kg
P(35<X<55)=P(35−455<Z<55−455)=P(−2<Z<2)=P(35<X<55)=P(\frac{35-45}{5}<Z<\frac{55-45}{5})=P(-2<Z<2)=P(35<X<55)=P(535−45<Z<555−45)=P(−2<Z<2)=
=P(Z<2)−P(Z<−2)=0.9545.=P(Z<2)-P(Z<-2)=0.9545.=P(Z<2)−P(Z<−2)=0.9545.
Number of children: n=1000∗0.9545=955.n=1000*0.9545=955.n=1000∗0.9545=955.
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