A sample of 25 elements from a normally distributed population is selected.the sample mean is 10.assuming a population standard deviationog 4, determine the 95%confidence interval for mean ?
95%CI=(xˉ−z0.025sn,xˉ+z0.025sn)=95\%CI=(\bar x-z_{0.025}\frac{s}{\sqrt{n}},\bar x+z_{0.025}\frac{s}{\sqrt{n}})=95%CI=(xˉ−z0.025ns,xˉ+z0.025ns)=
=(10−1.96425,10+1.96425)=(8.432,11.568).=(10-1.96\frac{4}{\sqrt{25}},10+1.96\frac{4}{\sqrt{25}})=(8.432,11.568).=(10−1.96254,10+1.96254)=(8.432,11.568).
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