A sample of 25 elements from a normally distributed population is selected.the sample mean is 10.assuming a population standard deviationog 4, determine the 95%confidence interval for mean ?
"95\\%CI=(\\bar x-z_{0.025}\\frac{s}{\\sqrt{n}},\\bar x+z_{0.025}\\frac{s}{\\sqrt{n}})="
"=(10-1.96\\frac{4}{\\sqrt{25}},10+1.96\\frac{4}{\\sqrt{25}})=(8.432,11.568)."
Comments
Leave a comment