Question #303109

a. List the sample space in the given experiment. How many outcomes are

possible?

b. Construct a table showing the number of defective computers in each

outcome and assign this number to this outcome. What is the value of the

random variable X?

c. Illustrate a probability distribution. What is the probability value P(X) to

each value of the random variable?

d. What is the sum of the probabilities of all values of the random

variable?

e. What do you notice about the probability of each value of the random

variable?


1
Expert's answer
2022-03-01T13:29:48-0500

a.There are 23=82^3=8 possible outcomes


S={DDD,DDN,DND,NDD,S=\{DDD, DDN, DND, NDD,

DNN,NDN,NND,NNN}DNN,NDN, NND, NNN\}


b. The possible values of the random variable XX are 0,1,2,3.0, 1, 2, 3.

We will assume that the probability of getting heads and tails is the same:


p=q=1/2p = q =1/2Possible OutcomesADDD3DDN2DND2NDD2DNN1NDN1NND1NNN0\def\arraystretch{1.5} \begin{array}{c:c} Possible \ Outcomes & A \\ \hline DDD & 3 \\ \hdashline DDN & 2 \\ \hdashline DND & 2 \\ \hdashline NDD & 2 \\ \hdashline DNN& 1 \\ \hdashline NDN & 1 \\ \hdashline NND & 1 \\ \hdashline NNN & 0 \\ \hdashline \end{array}



c. Construct the probability distribution of the random variable


x0123p(x)1/83/83/81/8\def\arraystretch{1.5} \begin{array}{c:c} x & 0 & 1 & 2 & 3 \\ \hline p(x) & 1/8 & 3/8 & 3/8 & 1/8 \end{array}

or


x0123p(x)0.1250.3750.3750.125\def\arraystretch{1.5} \begin{array}{c:c} x & 0 & 1 & 2 & 3 \\ \hline p(x) & 0.125 & 0.375 & 0.375 & 0.125 \end{array}



d.

P(X=0)+P(X=1)+P(X=2)+P(X=3)P(X=0)+P(X=1)+P(X=2)+P(X=3)

=1/8+3/8+3/8+1/8=1=1/8+3/8+3/8+1/8=1

e.

The probability of each value of a discrete random variable is between 0 and 1, and the sum of all the probabilities is equal to 1.



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