Question #302937

Find the 99th percentile of a normal curve


1
Expert's answer
2022-03-02T10:15:10-0500

For 99th percentile of the normal curve z-score is


P(Z<z)=0.99P(Z<z)=0.99


 

z=2.326348.z=2.326348.



The 99th percentile of a normal distribution =2.3263.


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