How large a sample should be taken to be 95% sure that the error of estimation does not exceed
0.2 unit when standard deviation is 5?
define the sample size n = ( (z * standard deviation) / (margin of error ) )2
z at 95% confidence from the normal table is 1.96
Thus substituting in the above, we obtain
sample size = ( 1.96 * 5 / 0.2 )2
= (49)2
= 2401
Comments
Leave a comment