Mrs. Paul wants to test that claim that, on average, her students' average mark is 85. She pulls the records of 100 per past student over a three-year period. The grades are inputted into MINITAB for analysis. Exhibit 1 below shows the results of an analysis carried out on the data obtained.
Exhibit 1
One-Sample Z: Level I/II
Test of mu = 85 vs mu not = 85 The assumed sigma = 15.0
Variable N Mean StDev SEMean Z P
Students Score 100 75.4 12.99 * ** ***
i. Calculate the SEMean]
ii. Construct a 98% confidence interval for the population scores of Mrs. Paul’s students.
iii. State the null and alternate hypotheses for this test.
iv. Calculate the missing value ** and use tables to approximate the value of ***.
v. Using a 1% level of significance, state the decision criteria for this test
vi. State the conclusion for the test and why
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