The probabilities of machine manufacturing 0,1,2,3,4 and 5 defective parts in one day are 0.75,0.17,0.04,0.025,0.01 and 0.05 respectively. Find the mean of the probability Distribution
mean = ( (0*0.75) + (1*0.17) + (2*0.04) + (3*0.025) + (4*0.01) + (5*0.05)
= 0.615 which is the required mean
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