Find the mean of the probability distribution of the random variable X which can take only values 2,4,5, and 9, given that P(2)=9/20, P(4)=1/20, P(5)=⅕, P(9)=3/10
For a probability distribution of a discrete random variable X, the mean is computed using the formula:
μX = Σ XiPi
Given
X 2 4 5 9
P(X) 9/20 1/20 1/5 3/10
Therefore, the mean;
μX = Σ XiPi = 2(9/20) + 4(1/20) + 5(1/5) + 9(3/10) = 4.8
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