Two balls are drawn in succession without replacement from a box containing 4 yellow balls and 3 white balls. Let Z be the random variable representing the number of white balls. Find the values of the random variable Z.
P(Z=0)=47∗36=27.P(Z=0)=\frac{4}{7}*\frac{3}{6}=\frac{2}{7}.P(Z=0)=74∗63=72.
P(Z=1)=37∗46∗2=47.P(Z=1)=\frac{3}{7}*\frac{4}{6}*2=\frac{4}{7}.P(Z=1)=73∗64∗2=74.
P(Z=1)=37∗26=17.P(Z=1)=\frac{3}{7}*\frac{2}{6}=\frac{1}{7}.P(Z=1)=73∗62=71.
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