Let X= lifetime of a certain kind of bulb: X∼N(μ,σ2).
Given μ=500h,σ=45h.
i)
P(X≥570)=1−P(X<570)
=1−P(Z<45570−500)
≈1−P(Z<1.555556)≈0.0599 5.99%
ii)
P(485<X<515)=P(X<515)−P(X≤485)
=P(Z<45515−500)−P(Z≤45485−500)
≈P(Z<0.333333)−P(Z<−0.333333)≈0.2611 26.11%
iii)
P(X≥x)=1−P(X<x)
=1−P(Z<45x−500)=0.05
45x−500≈1.6449x=45(1.6449)+500 x=574 hours
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