On the 3rd quarter examination in Statistics, the population mean was 70 and the population standard deviation was 9. Determine the standard score of a student who got a score of 88 assuming that the scores are normally distributed.
If X∼N(μ,σ2),X\sim N(\mu, \sigma^2),X∼N(μ,σ2), then Z=X−μσ∼N(0,1).Z=\dfrac{X-\mu}{\sigma}\sim N(0, 1).Z=σX−μ∼N(0,1).
Given μ=70,σ=9.\mu=70, \sigma=9.μ=70,σ=9.
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