In a National Achievement Test, suppose three test booklets are tested at random. Let D represent the defective test booklet and let N represent the non-defective test booklet. Let X be the random variable representing the number of non-defective test booklets
The number of possible outcomes = 23 = 8
Thus the sample space S = { DDD, DDN, DND, DNN, NNN, NND, NDN, NDD}
Define X as the random variable representing the number of non-defective test booklets, then
p(x=0) = 1/8
p(x=1) = 3/8
p(x=2) = 3/8
p(x=3) = 1/8
Hence we may represent the probability distribution as below
x 0 1 2 3
p(x) 1/8 3/8 3/8 1/8
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