Question

What is the probability of getting a sum that is multiples of 3 when two dice are thrown?

Answer 1

Favorable outcomes: {(1,2),(2,1),(1,5),(5,1),(3,3),(4,5),(5,4),(6,6)}.

Number of favorable outcomes: 8.

$P=\frac{8}{36}=\frac{2}{9}.$