Question

What is the chance of getting a sum of prime number when the sum of two dice are rolled?

Answer 1

Favorable outcomes = {(1,1),(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)}.

Total number of favorable outcomes = 15.

$P=\frac{15}{36}=\frac{5}{12}.$