Question #298591

The probability distribution of X, the number

of imperfections per 10 meters of a synthetic fabric in

continuous rolls of uniform width, is given by

x 01234

f(x) 0.41 0.37 0.16 0.05 0.01

Construct the cumulative distribution function of X.


1
Expert's answer
2022-02-17T04:28:33-0500
F(0)=P(X0)=P(X=0)=0.41F(0)=P(X\le0)=P(X=0)=0.41

F(1)=P(X1)=P(X=0 or X=1)F(1)=P(X\le1)=P(X=0\ or\ X=1)

=P(X=0)+P(X=1)=0.41+0.37=0.78=P(X=0)+P(X=1)=0.41+0.37=0.78

F(2)=P(X2)=P(X=0 or X=1 or X=2)F(2)=P(X\le2)=P(X=0\ or\ X=1\ or\ X=2)

=P(X=0)+P(X=1)+P(X=2)=P(X=0)+P(X=1)+P(X=2)

=0.78+0.16=0.94=0.78+0.16=0.94

F(3)=P(X3)=P(X=0)+P(X=1)F(3)=P(X\le3)=P(X=0)+P(X=1)

+P(X=2)+P(X=3)=0.94+0.05=0.99+P(X=2)+P(X=3)=0.94+0.05=0.99

F(4)=P(X4)=1F(4)=P(X\le4)=1

The cumulative distribution of XX is


F(x)={0x<00.410x<10.781x<20.942x<30.993x<41.00x1F(x) = \begin{cases} 0 &x<0 \\ 0.41 & 0\le x<1 \\ 0.78 & 1\le x<2 \\ 0.94 & 2\le x<3 \\ 0.99 & 3\le x<4 \\ 1.00 & x\ge 1 \end{cases}


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