Question #298348

An analysis of the monthly allowances received by a sample of five engineers


from a telco company has been conducted recently. The mean and median of


the allowances is RM7000. A unimodal among the observations is RM12,000.


Find the standard deviation if the allowances paid to each engineer were in full


thousands

Expert's answer

Mean μ=7000\mu=7000

x=12000

N=5


So,

1000=x−μσn  ⟹  σ5=12000−70001000  ⟹  σ=5×5=11.181000=\dfrac{x-\mu}{\frac{\sigma}{\sqrt{n}}}\\\implies \dfrac{\sigma}{\sqrt{5}}=\dfrac{12000-7000}{1000}\\\implies \sigma=5\times \sqrt{5}=11.18


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