Question

A spinner for a child's game has the numbers 1 through

9 evenly spaced. If a child spins, find each probability:

a. The number is divisible by 3.

Answer 1

Sample space = {1,2,3,4,5,6,7,8,9}

Total number of outcomes = 9

Number divisible by 3 in the sample space = 3, 6, 9 = No. of favourable outcomes

Required probability = $\frac{3}{9}=\frac{1}{3}$