Using the number 1,2,3,4,5 and 6 as the element of the populations
A.construct the sampling distribution of the sample mean and the probability histogram
The number of possible samples is "\\binom{N}{n}=\\binom{6}{3}=20".
The possible samples with their means are given below.
The sample means are derived from the formula,
"\\bar x_i={\\sum(x_i)\\over3}"
Sample mean
(1,2,3) 2
(1,2,4) 2.33
(1,2,5) 2.67
(1,2,6) 3
(1,3,4) 2.67
(1,3,5) 3
(1,3,6) 3.33
(1,4,5) 3.33
(1,4,6) 3.67
(1,5,6) 4
(2,3,4) 3
(2,3,5) 3.33
(2,3,6) 3.67
(2,4,5) 3.67
(2,4,6) 4
(2,5,6) 4.33
(3,4,5) 4
(3,4,6) 4.33
(3,5,6) 4.67
(4,5,6) 5
"a)"
The sampling distribution is,
"\\bar x_i" 2 2.33 2.67 3 3.33 3.67 4 4.33 4.67 5
"p(\\bar x _i)" "{0.05}" "{0.05}" "0.1" "0.15" "0.15" "0.15" "0.15" "0.1" "0.05" "0.05"
"b)"
The probability Histogram is given below.
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