Answer to Question #295911 in Statistics and Probability for Kim

Question #295911

a deck has four cards - an ace of spades, an ace of hearts, an ace of diamonds and an ace of club. two cards will be drawn with replacement. let H denote the number of the ace of hearts is drawn

1
Expert's answer
2022-02-10T13:42:59-0500

P(H=0)=3434=916.P(H=0)=\frac{3}{4}*\frac{3}{4}=\frac{9}{16}.

P(H=1)=1434+3414=616=38.P(H=1)=\frac{1}{4}*\frac{3}{4}+\frac{3}{4}*\frac{1}{4}=\frac{6}{16}=\frac{3}{8}.

P(H=2)=1414=116.P(H=2)=\frac{1}{4}*\frac{1}{4}=\frac{1}{16}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment