A bag contains 8 blue and 7 yellow balls. Two balls are drawn in succession without replacement. Find the probability that both the balls are of yellow color.
The total number of balls is, 8+7=15 balls.
The probability that a blue ball is selected is "p(blue)={8\\over15}"
The probability that a yellow ball is selected is "p(yellow)={7\\over15}"
The probability that two balls drawn in succession without replacement are both yellow in is "{7\\over15}\\times{6\\over14}={42\\over210}={1\\over5}"
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