Question

A bag contains 8 blue and 7 yellow balls. Two balls are drawn in succession without replacement. Find the probability that both the balls are of yellow color.

Answer 1

The total number of balls is, 8+7=15 balls.

The probability that a blue ball is selected is $p(blue)={8\over15}$

The probability that a yellow ball is selected is $p(yellow)={7\over15}$

The probability that two balls drawn in succession without replacement are both yellow in is ${7\over15}\times{6\over14}={42\over210}={1\over5}$