Question #293582

Let x denote the number of biased die with the following probability mass function p(x) 

X:    1    2   3    4   5     6

P(x):  1/6  1/6  1/5   y   1/5   1/6


a) find the value of y 

b) find the cdf of x


1
Expert's answer
2022-02-07T10:50:05-0500

a)


ip(xi)=1\sum_ip(x_i)=1

1/6+1/6+1/5+y+1/5+1/6=11/6+1/6+1/5+y+1/5+1/6=1

y=1/10y=1/10

b)


F(1)=P(X1)=P(1)=1/6F(1) =P(X\le 1)=P(1)= 1/6

F(2)=P(X2)=P(1)+P(2)=1/3F(2) =P(X\le 2)=P(1)+P(2)= 1/3

F(3)=P(X3)=P(1)+P(2)+P(3)=8/15F(3) =P(X\le 3)=P(1)+P(2)+P(3)= 8/15

F(4)=P(X4)=P(1)+P(2)+P(3)+P(4)F(4) =P(X\le4)=P(1)+P(2)+P(3)+P(4)

=19/30= 19/30

F(5)=P(X5)=P(1)+P(2)+P(3)+P(4)F(5) =P(X\le5)=P(1)+P(2)+P(3)+P(4)

+P(5)=5/6+P(5)=5/6

F(6)=P(X6)=P(1)+P(2)+P(3)+P(4)F(6)=P(X\le6)=P(1)+P(2)+P(3)+P(4)

+P(X=5)+P(X=6)=1+P(X=5)+P(X=6)=1

The cdf is


F(x)={0x<11/61x<21/32x<38/153x<419/304x<55/65x<61x6F(x)=\begin{cases} 0 &x<1 \\ 1/6 &1\le x< 2 \\ 1/3 &2\le x< 3 \\ 8/15 & 3\le x< 4 \\ 19/30 & 4\le x< 5 \\ 5/6 &5\le x< 6 \\ 1 & x\ge 6 \\ \end{cases}


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