Question #293562

Find the proportion area of the region between z= -2 and z= -3


Expert's answer

P(−3<Z<−2)=P(Z<−2)−P(Z<−3)=0.02275−0.0013499=0.0214P(-3<Z<-2)=P(Z<-2)-P(Z<-3)=0.02275-0.0013499=0.0214


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Guyana #340795 on Jan 2024