A box contains 6 red balls, 5 blue balls, and 10 green bas. In how many ways can you choose 2 red balls and 5 green balls
There are, 6 red balls, 5 blue balls, and 10 green balls.
The number of ways to choose 2 red balls out of 6 red balls is, "\\binom{6}{2}={6\\times 5\\over 2}=15"
The number of ways to choose 5 green balls out of 10 green balls is, "\\binom{10}{5}={10\\times 9\\times 8\\times 7\\times 6\\over 5\\times4\\times 3\\times2}=252"
Therefore, the number of ways to choose 2 red balls and 5 green balls is "15\\times252=3780" ways.
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