Given a standard normal distribution with mean =61 and standard deviation = 35, find P(X<113)
μ=61σ=35\mu=61\\\sigma=35μ=61σ=35
p(x<113)=p(x−μσ<113−μσ)=p(Z<113−6135)=p(Z<1.49)=0.93119p(x\lt 113)=p({x-\mu\over \sigma}\lt {113-\mu\over\sigma})=p(Z\lt{113-61\over35})=p(Z\lt1.49)=0.93119p(x<113)=p(σx−μ<σ113−μ)=p(Z<35113−61)=p(Z<1.49)=0.93119
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