Question

A random variable, Z, which has mean 0 and standard deviation 1, find (1) p(z>1.2) (2) p(-2.0<z<2.0) (3) p(-1.2<z<1.0)

Answer 1

(1) $P(Z>1.2)=1-P(Z<1.2)=0.1151.$

(2) $P(-2.0<Z<2.0)=P(Z<2)-P(Z<-2.0)=0.9544.$

(3) $P(-1.2<Z<1.0)=P(Z<1.0)-P(Z<-1.2)=0.7262.$