Question #292088
  1. X: the number of automobile accidents per year in Virginia.
1
Expert's answer
2022-01-31T15:53:36-0500

The question is incomplete, assume it as:


Let the total number of accidents in Virginia are 3500.

And X: the number of automobile accidents per year in Virginia, n(X)=2800n(X)=2800

and Y: the number of other accidents per year in Virginia.

What is the probability of an accident which is not automobile?


Solution:

n(S)=3500n(X)=2800n(Y)=35002800=700P(Y)=n(Y)n(S)=7003500=15n(S)=3500 \\n(X)=2800 \\ n(Y)=3500-2800=700 \\ P(Y)=\dfrac{n(Y)}{n(S)}=\dfrac{700}{3500}=\dfrac15

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