"An electrical firm manufactures light bulbs that have a length of life that is approximately normally distributed, with mean equal to 786 hours and a standard deviation of 80 hours. Find the probability that a random samples of 17 bulbs will have an average life between 799 and 802 hours."
we use z calculations
z(799) = (799 - 786) / 80 = 0.1625
z(802) = (802 - 786)/ 80 = 0.2
P(799<x<802) = P(0.1625<Z<0.2)
using the normal table we have
= ( 0.57926 - 0.56356) = 0.0157 which is the required probability
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